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TMUA Quadratics and the Discriminant

A quadratic is an expression ax2+bx+cax^2+bx+c with a≠0a\ne0. A question may ask what the roots, discriminant or vertex tell you, not just for the roots themselves.

Paper 1 and Paper 2 topic. Specification codes: MM1.3, M4.11, M4.16. Last checked 12 November 2026.

The discriminant

The discriminant is b2−4acb^2-4ac. Positive means two distinct real roots, zero means one repeated root, and negative means no real roots.

Completing the square

Write ax2+bx+cax^2+bx+c as a(x+p)2+qa(x+p)^2+q. The vertex is (−p,q)(-p,q), and qq is the minimum value when a>0a>0 (the maximum when a<0a<0).

Sum and product of roots

If x2+bx+c=0x^2+bx+c=0 has roots α\alpha and β\beta, then α+β=−b\alpha+\beta=-b and αβ=c\alpha\beta=c. This lets you evaluate symmetric expressions without solving.

Quick checks

The parabola y=ax2+bx+cy=ax^2+bx+c opens upwards if a>0a>0 and downwards if a<0a<0. Its axis of symmetry is x=−b2ax=-\dfrac b{2a}, and the two roots are symmetric about it.

If the coefficients are whole numbers and the discriminant is a perfect square, the roots are rational and the quadratic factorises.

Worked examples

Example 1

Find the values of kk for which x2+kx+(k+3)=0x^2+kx+(k+3)=0 has no real roots.

Show the worked solution

The discriminant is k2−4(k+3)=k2−4k−12=(k−6)(k+2)k^2-4(k+3)=k^2-4k-12=(k-6)(k+2). No real roots needs this to be negative, so −2<k<6-2<k<6.

Answer: −2<k<6-2<k<6

Example 2

Find the minimum value of 3x2−12x+53x^2-12x+5 and where it occurs.

Show the worked solution

3x2−12x+5=3(x−2)2−12+5=3(x−2)2−73x^2-12x+5=3(x-2)^2-12+5=3(x-2)^2-7. A square is at least 0, so the minimum is −7-7, at x=2x=2.

Answer: Minimum −7-7 at x=2x=2

Example 3

The roots of x2−5x+3=0x^2-5x+3=0 are α\alpha and β\beta. Find α2+β2\alpha^2+\beta^2.

Show the worked solution

α+β=5\alpha+\beta=5 and αβ=3\alpha\beta=3. So α2+β2=(α+β)2−2αβ=25−6=19\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha\beta=25-6=19.

Answer: 19

Common mistakes

  • Treating a zero discriminant as 'no roots': it gives one repeated real root.
  • Dropping the factor aa when completing the square, so the constant is wrong.
  • Using b2−4acb^2-4ac before the equation is rearranged to equal zero.
  • Giving the xx-value of the vertex when the question asks for the minimum value.

Test yourself on this topic with our free practice questions.

Quick answers

What does the discriminant tell you about a quadratic?

It shows how many real roots there are: b2−4ac>0b^2-4ac>0 gives two, =0=0 gives one repeated root, and <0<0 gives none.

How do you complete the square quickly?

Halve the coefficient of xx, square it, and adjust the constant. Take out any factor aa first.

Can I use the quadratic formula on the TMUA?

Yes, but the discriminant or a completed square is often faster, and there is no calculator for messy roots.

Practise it under timed conditions

A free timed sample paper with a worked solution for every question. No sign-up. For two full papers and a weak-spot drill, see Full Access.

Free sample paper

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