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TMUA Inequalities and Modulus

An inequality asks for a range of values rather than a single answer. The modulus ∣x∣|x| is the distance of xx from zero, so it is always non-negative.

Paper 1 and Paper 2 topic. Specification codes: MM1.5, M4.17, MM8.1. Last checked 12 November 2026.

Quadratic inequalities

Factorise, find the roots, and sketch the parabola. For an upward parabola, the expression is negative between the roots and positive outside them.

Linear inequalities

Treat them like equations, except that multiplying or dividing by a negative number reverses the inequality sign.

Modulus

  • ∣u∣<a|u|<a means −a<u<a-a<u<a.
  • ∣u∣>a|u|>a means u<−au<-a or u>au>a.
  • For ∣u∣≥∣v∣|u|\ge|v|, squaring both sides is safe because both sides are non-negative.

Using a sketch and test values

A sketch is the fastest check. For ∣x−2∣<3|x-2|<3, picture the V-shape centred at 2: it lies below 3 between −1-1 and 55.

For a combined condition such as x2>4x^2>4 and x<3x<3, solve each part separately and take the overlap, which here is x<−2x<-2 or 2<x<32<x<3. Then test one value from each region. A solution set that fails a test value is wrong, whatever the algebra said.

Squaring an inequality is only safe when both sides are non-negative: −3<2-3<2 but 9>49>4.

For a quadratic inequality with a negative leading coefficient, such as −x2+4x−3>0-x^2+4x-3>0, multiply by −1-1 and reverse the sign first, or sketch the downward parabola, which is positive between its roots.

Worked examples

Example 1

Solve x2−3x−10≤0x^2-3x-10\le0.

Show the worked solution

Factorise: (x−5)(x+2)≤0(x-5)(x+2)\le0. The parabola is below or on the axis between its roots, so −2≤x≤5-2\le x\le5.

Answer: −2≤x≤5-2\le x\le5

Example 2

Solve ∣2x−3∣<5|2x-3|<5.

Show the worked solution

−5<2x−3<5-5<2x-3<5, so −2<2x<8-2<2x<8 and −1<x<4-1<x<4.

Answer: −1<x<4-1<x<4

Example 3

Solve ∣x−1∣≥∣x+3∣|x-1|\ge|x+3|.

Show the worked solution

Square both sides: (x−1)2≥(x+3)2(x-1)^2\ge(x+3)^2, so −2x+1≥6x+9-2x+1\ge6x+9, giving −8≥8x-8\ge8x and x≤−1x\le-1.

Answer: x≤−1x\le-1

Common mistakes

  • Not reversing the inequality when multiplying or dividing by a negative.
  • Writing x2>4x^2>4 as x>2x>2 and forgetting x<−2x<-2.
  • Multiplying through by an expression whose sign is unknown.
  • Giving a one-piece answer to ∣u∣>a|u|>a, which has two separate pieces.

Test yourself on this topic with our free practice questions.

Quick answers

How do you solve a quadratic inequality?

Find the roots by factorising, sketch the parabola, and read off where it is above or below the axis.

What does the modulus sign mean in maths?

∣x∣|x| is the non-negative size of xx: ∣3∣=3|3|=3 and ∣−3∣=3|-3|=3.

Why do you flip the inequality sign when dividing by a negative?

Multiplying by a negative reverses order. For example 2<32<3 but −2>−3-2>-3.

Practise it under timed conditions

A free timed sample paper with a worked solution for every question. No sign-up. For two full papers and a weak-spot drill, see Full Access.

Free sample paper

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