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TMUA Indices and Surds

Indices are powers such as xnx^n, and surds are irrational roots such as 5\sqrt5. With no calculator, answers are left in exact form rather than as decimals.

Paper 1 and Paper 2 topic. Specification codes: MM1.1, MM1.2, M2.7, M2.11. Last checked 12 November 2026.

Index laws

  • am⋅an=am+na^m\cdot a^n=a^{m+n} and am÷an=am−na^m\div a^n=a^{m-n}.
  • (am)n=amn(a^m)^n=a^{mn}.
  • a−n=1ana^{-n}=\dfrac1{a^n} and am/n=(an)ma^{m/n}=\left(\sqrt[n]{a}\right)^m.

Simplifying surds

Pull out square factors: 12=23\sqrt{12}=2\sqrt3. Only like surds can be added, so 23+33=532\sqrt3+3\sqrt3=5\sqrt3.

Rationalising

To clear a surd from a denominator p+qp+\sqrt q, multiply top and bottom by p−qp-\sqrt q, using (p+q)(p−q)=p2−q(p+\sqrt q)(p-\sqrt q)=p^2-q.

Working without a calculator

Know your squares up to 15215^2, cubes up to 535^3 and powers of 2 up to 2102^{10}. They let you spot exact roots at a glance, such as 196=14\sqrt{196}=14 or 1253=5\sqrt[3]{125}=5.

When an equation has different bases, rewrite them with a common base. For example 4x=8x−14^x=8^{x-1} becomes 22x=23x−32^{2x}=2^{3x-3}, so x=3x=3. Fractional indices combine two ideas: 163/4=(164)3=23=816^{3/4}=\left(\sqrt[4]{16}\right)^3=2^3=8.

In surd questions, expand carefully and look for cancellation, because products of conjugates collapse to whole numbers.

Always simplify at the end. An option written as 533\dfrac{5\sqrt3}{3} and one written as 53\dfrac{5}{\sqrt3} are equal in value, so reduce your answer to a standard form and compare it with the options carefully. Negative indices on a fraction flip it, and a zero index gives 1 for any non-zero base.

Check by estimating: 50\sqrt{50} must be a little over 7, so 525\sqrt2 is plausible.

Worked examples

Example 1

Evaluate (278)−23\left(\dfrac{27}{8}\right)^{-\frac23}.

Show the worked solution

Invert to remove the negative: (827)2/3\left(\tfrac{8}{27}\right)^{2/3}. The cube root is 23\tfrac23, and squaring gives 49\tfrac49.

Answer: 49\tfrac49

Example 2

Write 63−3\dfrac{6}{3-\sqrt3} in the form a+b3a+b\sqrt3.

Show the worked solution

Multiply by 3+33+3\dfrac{3+\sqrt3}{3+\sqrt3}: the denominator is 9−3=69-3=6, so the result is 6(3+3)6=3+3\dfrac{6(3+\sqrt3)}{6}=3+\sqrt3.

Answer: 3+33+\sqrt3

Example 3

Simplify (2+5)2−(2−5)2(2+\sqrt5)^2-(2-\sqrt5)^2.

Show the worked solution

(2+5)2=9+45(2+\sqrt5)^2=9+4\sqrt5 and (2−5)2=9−45(2-\sqrt5)^2=9-4\sqrt5. The difference is 858\sqrt5.

Answer: 858\sqrt5

Common mistakes

  • Writing (a+b)2=a2+b2(a+b)^2=a^2+b^2 and missing the cross term, especially with surds.
  • Adding unlike surds, such as 2+3=5\sqrt2+\sqrt3=\sqrt5.
  • Applying a negative power to the sign instead of taking the reciprocal.
  • Rationalising with the same sign instead of the conjugate.

Test yourself on this topic with our free practice questions.

Quick answers

How do you rationalise a denominator?

Multiply top and bottom by the conjugate. For a\sqrt a multiply by a\sqrt a; for p+qp+\sqrt q multiply by p−qp-\sqrt q.

What does a fractional power mean?

The denominator is the root and the numerator is the power, so 82/3=(83)2=48^{2/3}=(\sqrt[3]{8})^2=4.

Can I leave surds in my answer?

Yes. Exact forms are expected, and the options will be written with surds or fractions.

Practise it under timed conditions

A free timed sample paper with a worked solution for every question. No sign-up. For two full papers and a weak-spot drill, see Full Access.

Free sample paper

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